Krull intersection theorem for Noetherian domains

This article defines a result where the base ring (or one or more of the rings involved) is Noetherian
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This fact is an application of the following pivotal fact/result/idea: Krull intersection theorem
View other applications of Krull intersection theorem OR Read a survey article on applying Krull intersection theorem

Statement

Let $R$ be a Noetherian domain (i.e. a Noetherian ring that is also an integral domain) and $I$ a proper ideal in $R$. Then, we have:

$\bigcap _{j=1}^{\infty }I^{j}=0$

Proof

Applying Krull intersection theorem for modules

The Krull intersection theorem states that if $M$ is a finitely generated module over a Noetherian ring $R$ and $I$ is an ideal inside $R$, then there exists $r\in I$ such that:

$(1-r)\left(\bigcap _{j=1}^{\infty }I^{j}M\right)=0$

We apply this to the case where $M=R$, to get that there exists $r\in I$, such that:

$(1-r)\left(\bigcap _{j=1}^{\infty }I^{j}\right)=0$

Applying the integral domain condition and properness of the ideal

Since $I$ is a proper ideal, $1\notin I$. Hence $r\neq 1$, so the element $1-r$ cannot be zero.

Thus, by the fact that we are in an integral domain, and by the above equation, we get:

$\bigcap _{j=1}^{\infty }I^{j}=0$