Graded Nakayama's lemma: Difference between revisions

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(New page: {{indispensable lemma}} ==Statement== Suppose <math>A</math> is a graded ring. Let <math>A^+</math> denote the ideal of all positively graded elements. Then, if <math>M</math> is an ...)
 
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Suppose <math>A</math> is a [[graded ring]]. Let <math>A^+</math> denote the ideal of all positively graded elements. Then, if <math>M</math> is an <math>A</math>-[[graded module]], <math>A^+M = M \implies M = 0</math>.
Suppose <math>A</math> is a [[graded ring]]. Let <math>A^+</math> denote the ideal of all positively graded elements. Then, if <math>M</math> is an <math>A</math>-[[graded module]], <math>A^+M = M \implies M = 0</math>.
==Related results==
* [[Nakayama's lemma]]

Revision as of 21:27, 8 February 2008

This article is about the statement of a simple but indispensable lemma in commutative algebra
View other indispensable lemmata

Statement

Suppose A is a graded ring. Let A+ denote the ideal of all positively graded elements. Then, if M is an A-graded module, A+M=MM=0.

Related results