Euclidean not implies norm-Euclidean: Difference between revisions
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<math>\mathbb{Z}\left[\frac{1 + \sqrt{69}{2}\right]</math> | <math>\mathbb{Z}\left[\frac{1 + \sqrt{69}}{2}\right]</math> | ||
is a [[Euclidean domain]], but is not norm-Euclidean. | is a [[Euclidean domain]], but is not norm-Euclidean. | ||
Revision as of 19:11, 5 January 2008
Statement
A ring of integers in a number field may be a Euclidean domain, even though it is not a norm-Euclidean domain. In other words, it may have a Euclidean norm which differs from its norm function, even if it is not Euclidean under its norm function.
Example
The ring:
is a Euclidean domain, but is not norm-Euclidean.
Proof (for example)
References
- A Quadratic Field which is Euclidean but not norm-Euclidean by David A. Clark, manuscripta math. 83, 327-330 (1994)