Euclidean not implies norm-Euclidean: Difference between revisions

From Commalg
No edit summary
(No difference)

Revision as of 19:10, 5 January 2008

Statement

A ring of integers in a number field may be a Euclidean domain, even though it is not a norm-Euclidean domain. In other words, it may have a Euclidean norm which differs from its norm function, even if it is not Euclidean under its norm function.

Example

The ring:

Failed to parse (syntax error): {\displaystyle \mathbb{Z}\left[\frac{1 + \sqrt{69}{2}\right]}

is a Euclidean domain, but is not norm-Euclidean.

Proof (for example)

References

  • A Quadratic Field which is Euclidean but not norm-Euclidean by David A. Clark, manuscripta math. 83, 327-330 (1994)