Filtrative Euclidean norm: Difference between revisions

From Commalg
No edit summary
 
(2 intermediate revisions by the same user not shown)
Line 1: Line 1:
{{wikilocal}}
{{Euclidean norm property}}
{{Euclidean norm property}}


==Definition==
==Definition==


A [[Euclidean norm]] on an [[integral domain]] is said to be '''filtrative''' if it satisfies the following equivalent conditions:
A [[Euclidean norm]] on a [[commutative unital ring]] is said to be '''filtrative''' if it satisfies the following condition:


* For any two elements of the domain, either their sum is zero or the norm of their sum is at most the maximum of the norms
The set of elements of norm at most<math>r</math>, along with zero, forms an additive subgroup. Thus, the association to each <math>r</math> of the corresponding subgroup forms a filtration of additive subgroups of the integral domain.
* The set of elements of norm at most<math>r</math>, along with zero, forms an additive subgroup. Thus, the association to each <math>r</math> of the corresponding subgroup forms a filtration of additive subgroups of the integral domain.


Clearly, any filtrative Euclidean norm is also uniquely Euclidean.
==Facts==


==Relation with other properties==
A filtrative Euclidean norm on an [[integral domain]] that is also [[multiplicatively monotone Euclidean norm|multiplicatively monotone]] is a [[uniquely Euclidean norm]]. {{proofat|[[Filtrative and multiplicatively monotone implies uniquely Euclidean]]}}
 
===Weaker properties===
 
* [[Uniquely Euclidean norm]]

Latest revision as of 17:21, 22 January 2009

BEWARE! This term is nonstandard and is being used locally within the wiki. For its use outside the wiki, please define the term when using it.
Learn more about terminology local to the wiki OR view a complete list of such terminology

This article defines a property that can be evaluated for a Euclidean norm on a commutative unital ring

Definition

A Euclidean norm on a commutative unital ring is said to be filtrative if it satisfies the following condition:

The set of elements of norm at most, along with zero, forms an additive subgroup. Thus, the association to each of the corresponding subgroup forms a filtration of additive subgroups of the integral domain.

Facts

A filtrative Euclidean norm on an integral domain that is also multiplicatively monotone is a uniquely Euclidean norm. For full proof, refer: Filtrative and multiplicatively monotone implies uniquely Euclidean