https://commalg.subwiki.org/w/index.php?action=history&feed=atom&title=Spectrum_is_T0Spectrum is T0 - Revision history2026-07-12T20:02:52ZRevision history for this page on the wikiMediaWiki 1.41.2https://commalg.subwiki.org/w/index.php?title=Spectrum_is_T0&diff=1232&oldid=prevVipul: 1 revision2008-05-12T16:34:46Z<p>1 revision</p>
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</td></tr></table>Vipulhttps://commalg.subwiki.org/w/index.php?title=Spectrum_is_T0&diff=1231&oldid=prevVipul: New page: {{spectrum topology fact}} ==Statement== ===Verbal statement=== The spectrum of a commutative unital ring is a T0 space: given any two points, it cannot happen that each one...2008-03-15T21:11:31Z<p>New page: {{spectrum topology fact}} ==Statement== ===Verbal statement=== The <a href="/wiki/Spectrum" class="mw-redirect" title="Spectrum">spectrum</a> of a <a href="/wiki/Commutative_unital_ring" title="Commutative unital ring">commutative unital ring</a> is a <a href="/w/index.php?title=T0_space&action=edit&redlink=1" class="new" title="T0 space (page does not exist)">T0 space</a>: given any two points, it cannot happen that each one...</p>
<p><b>New page</b></p><div>{{spectrum topology fact}}<br />
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==Statement==<br />
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===Verbal statement===<br />
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The [[spectrum]] of a [[commutative unital ring]] is a [[T0 space]]: given any two points, it cannot happen that each one is in the closure of the other one.<br />
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==Proof==<br />
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The proof follows directly from the following fact: given two prime ideals, such that each is contained in the other, the ideals must be equal.</div>Vipul