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	<title>Euclidean implies Dedekind-Hasse - Revision history</title>
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	<updated>2026-08-03T19:34:58Z</updated>
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		<id>https://commalg.subwiki.org/w/index.php?title=Euclidean_implies_Dedekind-Hasse&amp;diff=1820&amp;oldid=prev</id>
		<title>Vipul: New page: ==Statement==  ===Verbal statement===  Any fact about::Euclidean norm on a commutative unital ring is a fact about::Dedekind-Hasse norm.  ==Definitions used==  ===Euclidean nor...</title>
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		<updated>2009-01-23T18:32:27Z</updated>

		<summary type="html">&lt;p&gt;New page: ==Statement==  ===Verbal statement===  Any &lt;a href=&quot;/w/index.php?title=Fact_about::Euclidean_norm&amp;amp;action=edit&amp;amp;redlink=1&quot; class=&quot;new&quot; title=&quot;Fact about::Euclidean norm (page does not exist)&quot;&gt;fact about::Euclidean norm&lt;/a&gt; on a &lt;a href=&quot;/wiki/Commutative_unital_ring&quot; title=&quot;Commutative unital ring&quot;&gt;commutative unital ring&lt;/a&gt; is a &lt;a href=&quot;/w/index.php?title=Fact_about::Dedekind-Hasse_norm&amp;amp;action=edit&amp;amp;redlink=1&quot; class=&quot;new&quot; title=&quot;Fact about::Dedekind-Hasse norm (page does not exist)&quot;&gt;fact about::Dedekind-Hasse norm&lt;/a&gt;.  ==Definitions used==  ===Euclidean nor...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;==Statement==&lt;br /&gt;
&lt;br /&gt;
===Verbal statement===&lt;br /&gt;
&lt;br /&gt;
Any [[fact about::Euclidean norm]] on a [[commutative unital ring]] is a [[fact about::Dedekind-Hasse norm]].&lt;br /&gt;
&lt;br /&gt;
==Definitions used==&lt;br /&gt;
&lt;br /&gt;
===Euclidean norm===&lt;br /&gt;
&lt;br /&gt;
{{further|[[Euclidean norm]]}}&lt;br /&gt;
&lt;br /&gt;
===Dedekind-Hasse norm===&lt;br /&gt;
&lt;br /&gt;
{{further|[[Dedekind-Hasse norm]]}}&lt;br /&gt;
&lt;br /&gt;
==Related facts==&lt;br /&gt;
&lt;br /&gt;
* [[Dedekind-Hasse not implies Euclidean]]&lt;br /&gt;
&lt;br /&gt;
==Proof==&lt;br /&gt;
&lt;br /&gt;
===Key idea===&lt;br /&gt;
&lt;br /&gt;
The main idea here is that while the Euclidean condition allows us to find an element of the form &amp;lt;math&amp;gt;a - bq&amp;lt;/math&amp;gt; of smaller norm, the Dedekind-Hasse condition only requires some &amp;lt;math&amp;gt;R&amp;lt;/math&amp;gt;-linear combination of &amp;lt;math&amp;gt;a&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;b&amp;lt;/math&amp;gt; to have smaller norm. In particular, for the Dedekind-Hasse condition, we can pick &amp;lt;math&amp;gt;sa - bq&amp;lt;/math&amp;gt; with &amp;lt;math&amp;gt;s \ne 1&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
===Proof details===&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Given&amp;#039;&amp;#039;&amp;#039;: A commutative unital ring &amp;lt;math&amp;gt;R&amp;lt;/math&amp;gt; with a Euclidean norm &amp;lt;math&amp;gt;N&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;To prove&amp;#039;&amp;#039;&amp;#039;: &amp;lt;math&amp;gt;N&amp;lt;/math&amp;gt; is a Dedekind-Hasse norm on &amp;lt;math&amp;gt;R&amp;lt;/math&amp;gt;: given &amp;lt;math&amp;gt;a,b \in R&amp;lt;/math&amp;gt; with &amp;lt;math&amp;gt;b \ne 0&amp;lt;/math&amp;gt;, either &amp;lt;math&amp;gt;a \in (b)&amp;lt;/math&amp;gt; or there exists &amp;lt;math&amp;gt;r \in (a,b)&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;N(r) &amp;lt; N(b)&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Proof&amp;#039;&amp;#039;&amp;#039;: Since &amp;lt;math&amp;gt;b \ne 0&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;N&amp;lt;/math&amp;gt; is a Euclidean norm, we can write:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;a = bq + r&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where either &amp;lt;math&amp;gt;r = 0&amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt;N(r) &amp;lt; N(b)&amp;lt;/math&amp;gt;. Consider both cases:&lt;br /&gt;
&lt;br /&gt;
* &amp;lt;math&amp;gt;r = 0&amp;lt;/math&amp;gt;: In this case, &amp;lt;math&amp;gt;a = bq&amp;lt;/math&amp;gt;, so &amp;lt;math&amp;gt;a \in (b)&amp;lt;/math&amp;gt;, so the Dedekind-Hasse condition is satisfied.&lt;br /&gt;
* &amp;lt;math&amp;gt;N(r) &amp;lt; N(b)&amp;lt;/math&amp;gt;: In this case, &amp;lt;math&amp;gt;r = a - bq&amp;lt;/math&amp;gt;, so &amp;lt;math&amp;gt;r \in (a,b)&amp;lt;/math&amp;gt;, with &amp;lt;math&amp;gt;N(r) &amp;lt; N(b)&amp;lt;/math&amp;gt;, so the Dedekind-Hasse condition is satisfied.&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
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