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	<title>Artinian implies IZ - Revision history</title>
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	<updated>2026-08-30T15:47:05Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://commalg.subwiki.org/w/index.php?title=Artinian_implies_IZ&amp;diff=50&amp;oldid=prev</id>
		<title>Vipul: 1 revision</title>
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		<updated>2008-05-12T16:18:42Z</updated>

		<summary type="html">&lt;p&gt;1 revision&lt;/p&gt;
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				&lt;td colspan=&quot;1&quot; style=&quot;background-color: #fff; color: #202122; text-align: center;&quot;&gt;← Older revision&lt;/td&gt;
				&lt;td colspan=&quot;1&quot; style=&quot;background-color: #fff; color: #202122; text-align: center;&quot;&gt;Revision as of 16:18, 12 May 2008&lt;/td&gt;
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		<author><name>Vipul</name></author>
	</entry>
	<entry>
		<id>https://commalg.subwiki.org/w/index.php?title=Artinian_implies_IZ&amp;diff=49&amp;oldid=prev</id>
		<title>Vipul: New page: ==Statement==  ===Verbal statement===  Any Artinian ring is IZ: every element is either invertible, or a zero divisor.  ==Proof==  &#039;&#039;Given&#039;&#039;: An Artinian ring &lt;math&gt;A&lt;/math...</title>
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		<updated>2008-03-11T14:24:53Z</updated>

		<summary type="html">&lt;p&gt;New page: ==Statement==  ===Verbal statement===  Any &lt;a href=&quot;/wiki/Artinian_ring&quot; title=&quot;Artinian ring&quot;&gt;Artinian ring&lt;/a&gt; is &lt;a href=&quot;/w/index.php?title=IZ-ring&amp;amp;action=edit&amp;amp;redlink=1&quot; class=&quot;new&quot; title=&quot;IZ-ring (page does not exist)&quot;&gt;IZ&lt;/a&gt;: every element is either invertible, or a zero divisor.  ==Proof==  &amp;#039;&amp;#039;Given&amp;#039;&amp;#039;: An Artinian ring &amp;lt;math&amp;gt;A&amp;lt;/math...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;==Statement==&lt;br /&gt;
&lt;br /&gt;
===Verbal statement===&lt;br /&gt;
&lt;br /&gt;
Any [[Artinian ring]] is [[IZ-ring|IZ]]: every element is either invertible, or a zero divisor.&lt;br /&gt;
&lt;br /&gt;
==Proof==&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;Given&amp;#039;&amp;#039;: An Artinian ring &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt;, and an element &amp;lt;math&amp;gt;x \in A&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;To prove&amp;#039;&amp;#039;: &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; is invertible or a zero divisor&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;Proof&amp;#039;&amp;#039;: Consider the descending chain of ideals:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;A \supset (x) \supset (x^2) \supset \ldots&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
By the Artinianness, this chain stabilizes at some point, so we have:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;x^n = ax^{n+1}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
for some &amp;lt;math&amp;gt;a \in A&amp;lt;/math&amp;gt;. Rewriting, we see that:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;x^n( 1 - ax) = 0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
If &amp;lt;math&amp;gt;1 - ax = 0&amp;lt;/math&amp;gt;, then &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; is invertible. Otherwise, &amp;lt;math&amp;gt;x^n&amp;lt;/math&amp;gt; is a zero divisor, and hence &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; is a zero divisor.&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
	</entry>
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